🗿 🤹🏽 ♐️ Ikhtisar Penghitung Morris 👵🏾 🏥 🛩️

Menghitung jumlah elemen dalam aliran dengan cara terbatas dalam pandangan artis

_{Kami dengan senang hati mempersembahkan kepada Anda catatan yang ditulis oleh insinyur Qrator Labs Dmitry @ dimak24 Kamaldinov. Jika Anda ingin menjadi bagian dari tim Inti kami dan menangani tugas serupa - kirim email kepada kami di}_{hr@qrator.net}_.

1. Perkenalan

- : , ; : - 2 ^ n - 1 . , , . , .

, , — . , .

, ( 2). ( 3) , 1978 , . — . : , , , , .

2 ,

— . :

$\ begin {persamaan *} C_ {n + 1} = \ kiri \ {\ begin {array} {ll} C_n + 1 & \ textit {dengan probabilitas $ p = const $} \\ C_n & \ textit {dengan probabilitas $ 1 -p $.} \ End {larik} \ kanan. \ end {persamaan *}$

C_n - . , C_n . , C_n :

$\begin{align*} C_n \sim Bin(&n, p) \\ {\sf E} C_n = &np \\ {\sf D} C_n = &np(1-p). \end{align*}$

$\widehat{n}(C) := C/p$ . , : ${\sf E}\widehat{n}(C_n) = ({\sf E}C_n)/p = np/p = n$ .

: -, 1/p = const , , . -, . , n=1 100%. :

$\begin{align*} {\sf CV}\widehat{n}(C_n) = \frac{\sqrt{{\sf D}\widehat{n}(C_n)}}{{\sf E} \widehat{n}(C_n)} = \sqrt{\frac{1-p}{pn}}. \end{align*}$

3

, : 1, 1/2, 1/4 ..:

$\begin{equation*} C_{n+1} = \left\{\begin{array}{ll} C_n + 1 & \textit{ $2^{-C_n}$} \\ C_n & \textit{ $1 - 2^{-C_n}$.} \end{array}\right. \end{equation*}$

, ? x + 1 2^x , :

$\widehat{n}(C) := \sum_{i=0}^{C-1} 2^{i} = 2^C - 1.$

$\begin{align*} {\sf E}\left(2^{C_n} | C_{n-1} = y\right) =& \underbrace{2^{y + 1} 2^{-y}}_{\textit{ }} + \underbrace{2^y (1 - 2^{-y})}_{\textit{ }} = 2^y + 1 \implies \\ {\sf E}\left(2^{C_n}|C_{n-1}\right) =& 2^{C_{n-1}} + 1 \implies {\sf E}2^{C_n} = {\sf E}2^{C_{n-1}} + 1 = {\sf E}2^{C_{n-2}} + 2 = \dots \end{align*}$

0: C_0 = 0 , ${\sf E}2^{C_0} = 2^{0} = 1$ , ${\sf E} 2^{C_n} = \dots = n + 1$ . ${\sf E}\widehat{n}(C_n) = {\sf E}2^{C_n} - 1 = n$ .

$\widehat{n}(C_n)$ . , ${\sf D}\widehat{n} = {\sf E}\widehat{n}^2 - ({\sf E}\widehat{n})^2$ . , ${\sf E}\widehat{n}(C_n) = n$ . ${\sf E}\widehat{n}(C_n)^2$ . ,

$\begin{align*} {\sf E}\left(2^{C_n} - 1\right)^2 = {\sf E}2^{2C_n} - 2(n+1) + 1 = {\sf E}2^{2C_n} - 2n - 1. \end{align*}$

, , ${\sf E}2^{2C_n}$ .

$\begin{align*} {\sf E}\left(2^{2C_n} | C_{n-1} = y\right) &= \underbrace{2^{2(y + 1)} 2^{-y}}_{\textit{ }} + \underbrace{2^{2y}(1 - 2^{-y})}_{\textit{ }} = \\ 3 \cdot 2^y +2^{2y} &\implies {\sf E}\left(2^{2C_n} | C_{n-1}\right) = 3 \cdot 2^{C_{n-1}} + 2^{2C_{n-1}} \implies \\ {\sf E} 2^{2C_n} = 3n &+ {\sf E}2^{2C_{n-1}} = 3n + 3(n-1) + {\sf E}2^{2C_{n-2}} = \dots = \sum_{i=1}^n 3i \end{align*}$

$\begin{equation*} {\sf D}\widehat{n}(C_n) = \frac{3n(n+1)}{2} - 2n - 1 - n^2 = \frac{n^2 - n - 2}{2} \end{equation*}$ $\begin{equation*} {\sf CV}\widehat{n}(C_n) = \frac{\sqrt{{\sf D}\widehat{n}(C_n)}}{{\sf E}\widehat{n}(C_n)} = \sqrt{\frac{n^2-n-2}{2n^2}} \sim \frac{1}{\sqrt{2}}. \end{equation*}$

, , .

$\begin{align*} {\sf P}(|\widehat{n}(C_n) - n| \ge \varepsilon n) \le \frac{{\sf D}\widehat{n}(C_n)}{\varepsilon^2n^2} \sim \frac{1}{2\varepsilon^2}. \end{align*}$

, ${\bf X}$ $2^{2^{\bf X}} - 1$ . , $\mathcal{O}(\log \log n)$ !

4

: , . — < > — .

, , , — :

$\begin{align*} {\sf P}(n_{fail} = k) = (1 - 2^{-C})^k 2^{-C} \implies n_{fail} \sim Geom(2^{-C}). \end{align*}$

, , :

5

. , , , . , . , , - . , , EMA , .

: . ,

$\sum_{i=0}^{C-1} 2^i = 2^C - 1 =: n_0.$

, $2^{C-1} - 1 = \frac{1}{2}n_0 - \frac{1}{2}$ . , $\sim 2$ ! , $\frac{1}{2}$ :

6

: , ${\bf X}$ . : , , , (- ).

$\begin{align*} {\rm e}(C) &= C \gg {\bf M} \\ {\rm m}(C) &= C \& (2^{\bf M} - 1). \end{align*}$

$\begin{align*} C_{n+1} &= \left\{\begin{array}{ll} C_n + 1, & \textit{ $2^{-{\rm e}(C)}$} \\ C_n, & \textit{ $1 - 2^{-{\rm e}(C)}$} \end{array}\right. \\ \widehat{n}(C) &= (2^{{\rm e}(C)} - 1)2^{\bf M} + 2^{{\rm e}(C)}{\rm m}(C). \end{align*}$

, 2 C = 89 , ${\rm m} = 25$ ${\rm e} = 2$ . $\widehat{n} = (2^2 - 1) \times 2^5 + 2^2 \times 25 = 196$ .

, ( , ). ; , .

$\begin{align*} {\bf N}_{max} = 2^{2^{\bf E} + {\bf M}} - \left(2^{2^{\bf E} - 1} + 2^{\bf M}\right); \end{align*}$

, $\widehat{n}$ ${\rm m} = 2^{\bf M} - 1$ ${\rm e} = 2^{\bf E} - 1$ :

$\begin{align*} {\bf N}_{max} = \left(2^{2^{\bf E} - 1} - 1\right)2^{\bf M} + 2^{2^{\bf E} - 1}\left(2^{\bf M} - 1\right) = 2^{2^{\bf E} + {\bf M}} - \left(2^{2^{\bf E} - 1} + 2^{\bf M}\right) \end{align*}$

$\widehat{n}$ : ${\sf E}\widehat{n}(C_n) = n$ ;

${\sf E}(C_n | C_{n - 1} = y)$ . $y \equiv -1 \pmod{2^{\bf M}}$ ( ) $y \not\equiv -1 \pmod{2^{\bf M}}$ .

$\begin{align*} y \not\equiv -1 \pmod{2^{\bf M}} &\implies {\rm e}(y + 1) = {\rm e}(y), \quad {\rm m}(y + 1) = {\rm m}(y) + 1 \\ &\implies \widehat{n}(y + 1) = \widehat{n}(y) + 2^{{\rm e}(y)} \\ y \equiv -1 \pmod{2^{\bf M}} & \implies {\rm e}(y + 1) = {\rm e}(y) + 1,\\ &\phantom{\implies} \phantom{Z} {\rm m}(y) = 2^{\bf M} - 1, \quad {\rm m}(y + 1) = 0 \implies \\ \widehat{n}(y + 1) = \widehat{n}(y) &- 2^{{\rm e}(y)}\left(2^{\bf M} - 1\right) + 2^{{\rm e}(y) + {\bf M}} = \widehat{n}(y) + 2^{{\rm e}(y)} \end{align*}$

$\begin{align*} {\sf E}(2^{C_n} | C_{n-1} = y) &= \widehat{n}(y)\left(1 - 2^{-{\rm e}(y)}\right) + \left(\widehat{n}(y) + 2^{{\rm e}(y)}\right)2^{-{\rm e}(y)} = \widehat{n}(y) + 1. \end{align*}$

( ) ! , ( ):

$\begin{align*} {\sf CV}\widehat{n}(C_n) \le 2^{-\frac{{\bf M} + 1}{2}}. \end{align*}$

, 4, , , . , $2^{\bf M}$ . ( ), $2^{\bf M}$ . .

_._{. , , , . , :}

$\begin{align*} n \sim \underbrace{ NegativeBinomial\left(2^{-{\rm e}(C)}, 2^{\bf M} - {\rm m}(C)\right)}_{\textit{}} + \underbrace{\left(2^{\bf M} - {\rm m}(C)\right)}_{\textit{}}. \end{align*}$

, , :

, ( , $2^{\bf M}$ ).

$\begin{align*} \widehat{n}(C - 2^{\bf M}) = (2^{{\rm e}(C) - 1} - 1)2^{\bf M} + 2^{{\rm e}(C) - 1}{\rm m}(C) = 1/2\widehat{n}(C) - 2^{{\bf M} - 1}. \end{align*}$

, ${\bf M} > 0$ ( ) $2^{{\bf M} - 1} \in \mathbb{N}$ . , $2^{{\bf M} - 1}$ :

7

— ! !

, ...

8

$F : C \mapsto [0, 1]$ :

$\begin{equation*} C_{n+1} = \left\{\begin{array}{ll} C_n + 1 & \textit{ $F(C_n)$} \\ C_n & \textit{ $1 - F(C_n)$.} \end{array}\right. \end{equation*}$

$F(C_n) = 2^{-C_n}$ . :

$F(C_n) = 1 - \frac{C_n}{C_{max}},$

$C_{max}$ — , . , .

, . $x_1, \dots, x_m$ — :

$\begin{align*} \mathcal{H}_n(x_1, \dots x_m) = \sum_{\begin{array}{cc} & 0 \le i_j \le n \\ & i_1 + \dots + i_m = n \end{array}} x_1^{i_1} \cdots x_m^{i_m}. \end{align*}$

, , — . — : $\genfrac\{\}{0pt}{}{n}{m}$ — - . :

$\begin{align*} \genfrac\{\}{0pt}{}{n+m}{m} = \mathcal{H}_m(1, 2, \dots, m). \end{align*}$

$\mathcal{H}$ , :

$\begin{align*} {\sf P}(C_n = m) = \left[\prod_{k=0}^{m-1} F(k) \right] \mathcal{H}_{n-m}(1-F(1), \dots 1-F(m)). \end{align*}$

, : , , , : , .., — $\prod_{k=0}^{m-1} F(k)$ , n - m , : i_1 , i_2 .., $\mathcal{H}_{n-m}$ .

, $F(C) = 1 - \frac{C}{C_{max}}$

$\begin{equation*} {\sf P}(C_n = m) = \genfrac\{\}{0pt}{}{n}{m} \frac{C_{max}!}{(C_{max} - m)!C_{max}^n}. \end{equation*}$

. , ( ). — .

C_n ( , , ${\sf P}$ ):

$\begin{align*} {\sf E}C_n &= C_{max}\left(1 - \left(1 - \frac{1}{C_{max}}\right)^n\right) \\ {\sf D}C_n &= C_{max}^2\left(\frac{1}{C_{max}}\left(1 - \frac{1}{C_{max}}\right)^n + \left(1 - \frac{1}{C_{max}}\right)\left(1 - \frac{2}{C_{max}}\right)^n - \left(1 - \frac{1}{C_{max}}\right)^{2n}\right). \end{align*}$